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arithmetic_structure_of_complex_numbers [2014/01/29 19:22]
nikolaj
arithmetic_structure_of_complex_numbers [2014/01/29 19:35]
nikolaj
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 For $a,​b\in\mathbb R$ and $z,​u\in\mathbb C$ and $n,​k\in\mathbb N$, we have  For $a,​b\in\mathbb R$ and $z,​u\in\mathbb C$ and $n,​k\in\mathbb N$, we have 
  
-$\bullet\ ​\frac{1}{a+ib}=\frac{1}{a^2+b^2}(a-ib)$,+$ \frac{1}{a+ib}=\frac{1}{a^2+b^2}(a-ib)$ ​
 +^ $\frac{1}{z}=\frac{1}{|z|^2}\overline{z}$ ^
  
-or +and
  
-$\bullet\ \frac{1}{z}=\frac{1}{|z|^2}\overline{z}$+^ $ |z+u|^2=|z|^2+\mathrm{Re}(z\cdot\overline{u})+|u|^2 $ ^ 
- +$ \mathrm{Re}(z\cdot\overline{u})\le |z\cdot\overline{u}| $ ^ 
-and also +$ |\sum_{k=1}^n z_k|\le \sum_k^n|z_k| $ ^
- +
-$\bullet\ ​|z+u|^2=|z|^2+\mathrm{Re}(z\cdot\overline{u})+|u|^2$+
- +
-$\bullet\ ​\mathrm{Re}(z\cdot\overline{u})\le |z\cdot\overline{u}|$+
- +
-$\bullet\ ​|\sum_{k=1}^n z_k|\le \sum_k^n|z_k|$.+
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