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cardinal_arithmetic_with_types [2014/03/30 20:19]
nikolaj
cardinal_arithmetic_with_types [2014/03/30 20:19]
nikolaj
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 For $A$ is a type of only two terms $\mathcal{l},​\mathcal{r}:​A$ and $B(\mathcal{l}):​=X,​ B(\mathcal{r}):​=Y$,​ we get  For $A$ is a type of only two terms $\mathcal{l},​\mathcal{r}:​A$ and $B(\mathcal{l}):​=X,​ B(\mathcal{r}):​=Y$,​ we get 
-  * $\sum(x:​A).\,​B(x)=X+Y$+  * $\sum(x:​A).\,​B(x)=B(\mathcal{l})+B(\mathcal{r})=X+Y$
 For $B$ being constant (think of how the fibration looks like), we get For $B$ being constant (think of how the fibration looks like), we get
   * $\sum(x:​A).\,​B(x)=\sum(x:​A).\,​B=A\times B$   * $\sum(x:​A).\,​B(x)=\sum(x:​A).\,​B=A\times B$
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