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cardinal_arithmetic_with_types [2014/03/30 20:19] nikolaj |
cardinal_arithmetic_with_types [2014/03/30 20:20] nikolaj |
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For $B$ being constant (think of how the fibration looks like), we get | For $B$ being constant (think of how the fibration looks like), we get | ||
* $\sum(x:A).\,B(x)=\sum(x:A).\,B=A\times B$ | * $\sum(x:A).\,B(x)=\sum(x:A).\,B=A\times B$ | ||
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* $\prod(x:A).\,B(x)=\prod(x:A).\,B=A\to B$ | * $\prod(x:A).\,B(x)=\prod(x:A).\,B=A\to B$ | ||