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dependent_product_functor [2015/08/17 14:44]
nikolaj
dependent_product_functor [2015/10/13 20:50]
nikolaj
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 == Explanation starting from the exp-hom adjunction == == Explanation starting from the exp-hom adjunction ==
-A function space $Y^X$ can be characterized by the isomorphism $(A\to Y^X)\cong((A\times X)\to Y)$. Setting $\theta'​(\langle a,​x\rangle):​=\langle \theta(a),​x\rangle$ lets us moreover identify $(A\times X)\to Y$ with the space of function from that $\theta':​(A\times X)\to (Y\times X)$ with the additional requirement that the second component is mapped to itself.+A function space $Y^X$ can be characterized by the isomorphism $(A\to Y^X)\cong((A\times X)\to Y)$.  
 +Let us moreover identify $(A\times X)\to Y$ with the space of function from that $(A\times X)\to (Y\times X)$ with the additional requirement that the second component is mapped to itself, i.e. according to the scheme  
 +$\theta'​(\langle a,​x\rangle):​=\langle \theta(a),​x\rangle$.
  
 Again, in diagrams: Functions in Again, in diagrams: Functions in
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