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dependent_product_functor [2015/08/17 14:44] nikolaj |
dependent_product_functor [2015/10/13 20:50] nikolaj |
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== Explanation starting from the exp-hom adjunction == | == Explanation starting from the exp-hom adjunction == | ||
- | A function space $Y^X$ can be characterized by the isomorphism $(A\to Y^X)\cong((A\times X)\to Y)$. Setting $\theta'(\langle a,x\rangle):=\langle \theta(a),x\rangle$ lets us moreover identify $(A\times X)\to Y$ with the space of function from that $\theta':(A\times X)\to (Y\times X)$ with the additional requirement that the second component is mapped to itself. | + | A function space $Y^X$ can be characterized by the isomorphism $(A\to Y^X)\cong((A\times X)\to Y)$. |
+ | Let us moreover identify $(A\times X)\to Y$ with the space of function from that $(A\times X)\to (Y\times X)$ with the additional requirement that the second component is mapped to itself, i.e. according to the scheme | ||
+ | $\theta'(\langle a,x\rangle):=\langle \theta(a),x\rangle$. | ||
Again, in diagrams: Functions in | Again, in diagrams: Functions in |