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diagonal_functor [2014/09/26 15:35]
nikolaj
diagonal_functor [2014/09/26 15:48]
nikolaj
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 ==== Discussion ==== ==== Discussion ====
-=== Elaboration ​=== +=== Coherence ​=== 
 Note that for constant functors $\Delta_A,​\Delta_B$,​ the square in the definition of a natural transformation commutes trivially. Hence any arrow $f:{\bf C}[A,B]$ gives rise to a natural transformation. Note that for constant functors $\Delta_A,​\Delta_B$,​ the square in the definition of a natural transformation commutes trivially. Hence any arrow $f:{\bf C}[A,B]$ gives rise to a natural transformation.
  
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