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exponential_function [2016/07/10 15:08]
exponential_function [2019/10/06 17:26] (current)
nikolaj typo
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 We have  We have 
-$\left(x+y\right)^m=\sum_{k=0}^m \dfrac{n!}{k!\,​(m-k)!} x^k y^{m-k}$+$\left(x+y\right)^m=\sum_{k=0}^m \dfrac{m!}{k!\,​(m-k)!} x^k y^{m-k}$
 so so
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