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growing_sequence [2013/09/08 15:42]
nikolaj
growing_sequence [2013/09/08 15:43]
nikolaj
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 For growing sequences we have: $\lim_{n\to\infty}A_n=\bigcup_{n=1}^\infty A_n$. For growing sequences we have: $\lim_{n\to\infty}A_n=\bigcup_{n=1}^\infty A_n$.
 === Predicates === === Predicates ===
-| @#FFBB00: $A_n\uparrow \hat A \equiv ​(A\in \mathrm{GrowingSequence}(X))\land(\lim_{n\to\infty}A_n=\hat A)$ |+| @#EEEE55: $A_n\uparrow \hat A \equiv A\in \mathrm{GrowingSequence}(X)\land\lim_{n\to\infty}A_n=\hat A$ |
 ==== Parents ==== ==== Parents ====
 === Subset of === === Subset of ===
 [[Infinite sequence]] [[Infinite sequence]]
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