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holomorphic_function [2015/01/29 13:05]
nikolaj
holomorphic_function [2015/01/29 13:05]
nikolaj
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 For functions like the complex conjugation,​ $f(z):​=\overline{z}$,​ the finite difference For functions like the complex conjugation,​ $f(z):​=\overline{z}$,​ the finite difference
  
-$\dfrac{f(z)-f(0)}{z-0}=\dfrac{\overline{z}}{z}={\mathrm e}^{-2i\mathrm{arg}(z)}$+$\dfrac{f(z)-f(0)}{z-0}=\dfrac{\overline{z}}{z}={\mathrm e}^{-2i\,\mathrm{arg}(z)}$
  
 varies strongly with the $z$'s argument, even if $z$ is varied in only an arbitrarily small area around $0$, and so there is no limit. The function $f$ doesn'​t have a derivative. varies strongly with the $z$'s argument, even if $z$ is varied in only an arbitrarily small area around $0$, and so there is no limit. The function $f$ doesn'​t have a derivative.
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