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means_._note [2015/06/20 17:05]
nikolaj
means_._note [2016/03/09 10:34]
nikolaj
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 ===== Means . Note === ===== Means . Note ===
 ==== Note ==== ==== Note ====
-| @#55CCEE: context ​    | @#55CCEE: $S\subseteq X$ |+| @#55CCEE: context ​    | @#55CCEE: $S$ ... set |
 | @#55CCEE: context ​    | @#55CCEE: $G$ ... group | | @#55CCEE: context ​    | @#55CCEE: $G$ ... group |
 | @#55CCEE: context ​    | @#55CCEE: $w:S\to G$ | | @#55CCEE: context ​    | @#55CCEE: $w:S\to G$ |
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 | @#FFBB00: definiendum | @#FFBB00: $M:(S\to G)\to G$ | | @#FFBB00: definiendum | @#FFBB00: $M:(S\to G)\to G$ |
 | @#FFBB00: definiendum | @#FFBB00: $\langle f\rangle:​=I(f\cdot w)\cdot I(w)^{-1}$ | | @#FFBB00: definiendum | @#FFBB00: $\langle f\rangle:​=I(f\cdot w)\cdot I(w)^{-1}$ |
 +
 +Here $(f\cdot w)(s):​=f(s)*w(s)$ where $*$ is the group Operation.
  
 == Real functions == == Real functions ==
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 == Minus twelve == == Minus twelve ==
- +For $z\in(0,​1)$,​ we find
-I use this in the context of [[Minus twelve . Note]]. ​For $z\in(0,​1)$,​ we find+
  
 $\sum_{k=0}^\infty \langle q\mapsto q\,​z^q\rangle_{[k,​k+1]}=\dfrac{1}{\ln(z)^2}$,​ $\sum_{k=0}^\infty \langle q\mapsto q\,​z^q\rangle_{[k,​k+1]}=\dfrac{1}{\ln(z)^2}$,​
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 $\sum_{k=0}^\infty \left(k\,​z^k-\langle q\mapsto q\,​z^q\rangle_{[k,​k+1]}\right)=\dfrac{z}{(z-1)^2}-\dfrac{1}{\ln(z)^2}=-\dfrac{1}{12}+{\mathcal O}\left((z-1)^1\right)$ $\sum_{k=0}^\infty \left(k\,​z^k-\langle q\mapsto q\,​z^q\rangle_{[k,​k+1]}\right)=\dfrac{z}{(z-1)^2}-\dfrac{1}{\ln(z)^2}=-\dfrac{1}{12}+{\mathcal O}\left((z-1)^1\right)$
 +
 +See [[Minus twelve . Note]].
  
 ----- -----
 === Requirements === === Requirements ===
-[[Function integral]]+[[Function integral]], [[Classical probability density function]]
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