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minus_twelve_._note [2016/05/31 20:38]
nikolaj
minus_twelve_._note [2016/11/11 21:48]
nikolaj
Line 42: Line 42:
  
 $\dfrac {1} { \log(1+r)} = \dfrac {1} {r} \dfrac {1} {1 - \dfrac{1}{2}r + \dfrac{1}{3}r^2 + {\mathcal O}(r^3) } = \dfrac {1} {r} \left( 1 + \dfrac{1}{2} r - \dfrac{1}{2\cdot 2\cdot 3} r^2 + {\mathcal O}(r^3) \right) = \dfrac {1} {r} + \dfrac{1}{2} - \dfrac{1}{12} r + {\mathcal O}(r^2)$ $\dfrac {1} { \log(1+r)} = \dfrac {1} {r} \dfrac {1} {1 - \dfrac{1}{2}r + \dfrac{1}{3}r^2 + {\mathcal O}(r^3) } = \dfrac {1} {r} \left( 1 + \dfrac{1}{2} r - \dfrac{1}{2\cdot 2\cdot 3} r^2 + {\mathcal O}(r^3) \right) = \dfrac {1} {r} + \dfrac{1}{2} - \dfrac{1}{12} r + {\mathcal O}(r^2)$
 +
 +<​code>​
 +Plot[{
 +  Log[1 + r]
 +  , 1/Log[1 + r] - 1/r
 +  , 1/Log[1 + r]
 +  , 1/2 + (-1/12) r
 +  }, {r, -0.5, 1.5}, PlotRange -> {-0.5, 1.5}]
 +</​code>​
  
 With $r=z-1$ we see  With $r=z-1$ we see 
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