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quantum_integer [2014/12/09 22:25]
nikolaj
quantum_integer [2014/12/10 12:01]
nikolaj
Line 13: Line 13:
 In fact this doesn'​t require $n$ to be an integer. In fact this doesn'​t require $n$ to be an integer.
  
-The case $f=0$ is often considered, and also $[n]_{q^2}$ together with $f=n-1$, where the numbers are of the form $n+\mathcal{O}\left((q-1)^2\right)$. In the imaginary direction, $q\propto\mathrm{e}^{i\varphi}$,​ this corresponds to $\lim_{\varphi\to 0}\frac{\sin(n\varphi)}{\sin(\phi)}=n$. +Quantum aspect: ​The case $f=0$ is often considered, and also $[n]_{q^2}$ together with $f=n-1$, where the numbers are of the form $n+\mathcal{O}\left((q-1)^2\right)$. In the imaginary direction, $q\propto\mathrm{e}^{i\varphi}$,​ this corresponds to $\lim_{\varphi\to 0}\frac{\sin(n\varphi)}{\sin(\phi)}=n$. 
- +With $q=r\mathrm{e}^{i\varphi}$,​ along the positive real axis number $[n]_q$ is a valley with bottom at $q=1$, where $[n]_{1}=n$,​ and along $\varphi$ you have harmonic oscillations with period depending on $n$.
-Then, with $q=r\mathrm{e}^{i\varphi}$,​ along the positive real axis number $[n]_q$ is a valley with bottom at $q=1$, where $[n]_{1}=n$,​ and along $\varphi$ you have harmonic oscillations with period depending on $n$.+
  
 >I might change the exponent in $-f(n)/2$ to something else later >I might change the exponent in $-f(n)/2$ to something else later
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