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rational_numbers [2014/12/27 19:32]
nikolaj
rational_numbers [2016/04/23 13:49]
nikolaj
Line 8: Line 8:
  
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 === Discussion === === Discussion ===
 +== Theorems ==
 +For all $m$
 +
 +^ $\sum_{k=0}^m x^k = \dfrac{1}{1-x}(1-x^{m+1})$ ^
 +^ $\sum_{k=0}^m (1-y)^k = \dfrac{1}{y}-\dfrac{1}{y}(1-y)^{m+1}$ ^
 +
 +== Logic ==
 In first order logic, being of characteristic zero ("​$\forall n.\,​(1+1+\dots+1)_{n\ \text{times}}\neq 0$") requires an axiom schema. But even the induction axiom of the Peano axioms requires a schema. In first order logic, being of characteristic zero ("​$\forall n.\,​(1+1+\dots+1)_{n\ \text{times}}\neq 0$") requires an axiom schema. But even the induction axiom of the Peano axioms requires a schema.
  
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