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real_logarithm [2016/02/10 14:55]
nikolaj
real_logarithm [2016/02/10 14:56]
nikolaj
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 Consider Consider
  
-$\log_r(r^n/​r^k) = \log_r(r^n) - \log_r(r^k) = n-k$+$\log_r(r^n/​r^k) = \log_r(r^{n-k}= n-k = \log_r(r^n\log_r(r^k)$
  
 vs. vs.
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