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vector_space_basis [2013/09/07 19:31]
nikolaj
vector_space_basis [2014/12/02 16:37]
nikolaj
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 ===== Vector space basis ===== ===== Vector space basis =====
-==== Definition ​==== +==== Set ==== 
-| @#88DDEE: $V$...$\ \mathcal F$-vector space |+| @#55CCEE: context ​    | @#55CCEE: $V$...$\ \mathcal F$-vector space |
  
-| @#FFBB00: $B\in \mathrm{basis}(V)$ |+| @#FFBB00: definiendum ​| @#FFBB00: $B\in \mathrm{basis}(V)$ |
  
-| @#88DDEE: $B\subset V$ |+| @#55CCEE: context ​    | @#55CCEE: $B\subset V$ |
  
-| $B'​\subseteq B$ | $B'​$...finite | @#DDDDDD: $n\equiv\mathrm{card}(B')$ |+| $B'​\subseteq B$ | $B'​$...finite ​| @#DDDDDD: range       | @#DDDDDD: $n\equiv\left|(B'\right|$ |
  
 | $v_1,​\dots,​v_n\in B'$ | | $v_1,​\dots,​v_n\in B'$ |
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 | $x\in V$ | | $x\in V$ |
  
-| @#55EE55: $\sum_{k=1}^n c_k\cdot v_k=0\ \Rightarrow\ \forall j.\ c_j=0$ |+| @#55EE55: postulate ​  | @#55EE55: $\sum_{k=1}^n c_k\cdot v_k=0\ \Rightarrow\ \forall j.\ c_j=0$ |
  
 All finite subsets of the base are linearly independed. It's maybe more clear when written in the contrapositive:​ "​$\exists j.\ c_j\ne 0\ \Rightarrow\ \sum_{k=1}^n c_k\cdot v_k\ne 0$." All finite subsets of the base are linearly independed. It's maybe more clear when written in the contrapositive:​ "​$\exists j.\ c_j\ne 0\ \Rightarrow\ \sum_{k=1}^n c_k\cdot v_k\ne 0$."
  
-| @#55EE55: $\exists c_1,​\dots,​c_n.\ (x=\sum_{k=1}^n c_k\cdot v_k)$ |+| @#55EE55: postulate ​  | @#55EE55: $\exists c_1,​\dots,​c_n.\ (x=\sum_{k=1}^n c_k\cdot v_k)$ |
  
 For each basis $B$, every vector $x\in V$ has representation as linear combination. ​ For each basis $B$, every vector $x\in V$ has representation as linear combination. ​
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 Wikipedia: [[http://​en.wikipedia.org/​wiki/​Vector_space|Vector space]] Wikipedia: [[http://​en.wikipedia.org/​wiki/​Vector_space|Vector space]]
 ==== Parents ==== ==== Parents ====
-=== Requirements ​===+=== Context ​===
 [[Vector space]], [[Set cardinality]],​ [[Finite sum over a monoid]] [[Vector space]], [[Set cardinality]],​ [[Finite sum over a monoid]]
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