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x_x [2016/04/05 09:32]
nikolaj
x_x [2016/04/05 09:33] (current)
nikolaj
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 ^ $x^x={\mathrm e}^{x\log(x)}=\left({\mathrm e}^x\right)^{\log(x)}$ ^ ^ $x^x={\mathrm e}^{x\log(x)}=\left({\mathrm e}^x\right)^{\log(x)}$ ^
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 +>todo: write down the above with an expanded $\log$ to third order
  
 Because of this, the local minimum of $x^x$ is that of $x\log(x)$, namely $\frac{1}{\mathrm e}\approx 0.37$, and then see Because of this, the local minimum of $x^x$ is that of $x\log(x)$, namely $\frac{1}{\mathrm e}\approx 0.37$, and then see
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