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counit-unit_adjunction [2016/01/03 15:17] nikolaj |
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| There is also the combined case where you have an equivalence where the natural transformations are related in the sense of above - this is called an adjoint equivalence. | There is also the combined case where you have an equivalence where the natural transformations are related in the sense of above - this is called an adjoint equivalence. | ||
| - | For another perspective relating to universal morphisms, see [[On universal morphisms]] (31.10.2014). | + | == Inducing hom-set adjunctions == |
| + | Say you're given an arrow $f$ from or to the images of one of the functors (in either ${\mathrm{Hom}}(FX,Y)$ or ${\mathrm{Hom}}(X,GY)$). We can now pre- or post-compose with arrows formed from $\eta$ and $\epsilon$, use the functors on arrows and thus algebraically find an image of $f$ in the other category. | ||
| - | ... | + | Of course, each identity morphisms $1_{FX}:{\mathrm{Hom}}(FX,FX)$ in ${\bf C}$ corresponds to a component $\eta_X:{\mathrm{Hom}}(X,GFX)$ of $\eta:1_{\bf D}\xrightarrow{\bullet}GF$. And the claim here is that not only |
| - | + | ||
| - | Emphasis: Having an adjoint functor pair really means you also got a nice pair of natural transofmrations (for which functors are only a conditions). Given any functor $G$ (w.l.o.g, say you're in ${\bf D}$ and the functor out of it is $G$), then if there is an $F$ so that $F\dashv G$, you got yourself a [[monad]]. | + | |
| - | + | ||
| - | Each identity morphisms $1_{FX}$ in ${\bf C}$ corresponds to a component $\eta_X$ of $\eta:1_{\bf D}\xrightarrow{\bullet}GF$. And not only | + | |
| $1_{FX}\leftrightarrow \eta_X$ | $1_{FX}\leftrightarrow \eta_X$ | ||
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| ^ ${\mathrm{Hom}}(FX,Y)\cong{\mathrm{Hom}}(X,GY)$ ^ | ^ ${\mathrm{Hom}}(FX,Y)\cong{\mathrm{Hom}}(X,GY)$ ^ | ||
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| + | == As universals == | ||
| + | |||
| + | For another perspective relating to universal morphisms, see [[On universal morphisms]] (31.10.2014). | ||
| + | |||
| + | == To monads == | ||
| + | |||
| + | Having an adjoint functor pair really means you also got a nice pair of natural transofmrations (for which functors are only a conditions). Given any functor $G$ (w.l.o.g, say you're in ${\bf D}$ and the functor out of it is $G$), then if there is an $F$ so that $F\dashv G$, you got yourself a [[monad]]. | ||
| === Theorems === | === Theorems === | ||
