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exponential_function [2015/12/09 16:06]
nikolaj
exponential_function [2016/07/10 15:04]
nikolaj
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 ^ $\mathrm{e}^z \neq 0 $ ^ ^ $\mathrm{e}^z \neq 0 $ ^
  
-^ $\frac{\mathrm d}{\mathrm d z}\mathrm{e}^{f(z)} = \frac{\mathrm d}{\mathrm ​d z}f(z)\cdot \mathrm{e}^{f(z)} $ ^+^ $\frac{\mathrm d}{\mathrm d z}\mathrm{e}^{f(z)} = \frac{\mathrm d}{\mathrm ​dz}f(z)\cdot \mathrm{e}^{f(z)} $ ^
  
 $a,​b,​r,​\theta\in\mathbb R$ $a,​b,​r,​\theta\in\mathbb R$
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 $\left(x+y\right)^m=\sum_{k=0}^m \dfrac{n!}{k!\,​(m-k)!} x^k y^{m-k}$ $\left(x+y\right)^m=\sum_{k=0}^m \dfrac{n!}{k!\,​(m-k)!} x^k y^{m-k}$
 +
 +so
 +
 +$\left(1 + b_n\,x \right)^n = \sum_{k=0}^n \left( \dfrac {1} {b_n^k}\dfrac {n!} {(n-k)!} \right) \dfrac {x^k} {k!}$
  
 so so
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