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sine_function [2015/07/03 15:50]
nikolaj
sine_function [2015/11/04 16:24]
nikolaj
Line 12: Line 12:
  
 == Theorem == == Theorem ==
 +
 +  * From 
 +$\sum_{n=a}^{b}{\mathrm e}^{2kn}=\sum_{n=a}^{b}\left({\mathrm e}^{2k}\right)^n=\dots$ ​
 +
 +we get
  
 $\sum_{n=a}^{b}\sin(2kn)=\dfrac{\sin (k (a-b-1)) \sin (k (a+b))} {\sin(k)}$ $\sum_{n=a}^{b}\sin(2kn)=\dfrac{\sin (k (a-b-1)) \sin (k (a+b))} {\sin(k)}$
  
-But that's really just coming from $\sum_{n=a}^{b}{\mathrm e}^{2kn}=\sum_{n=a}^{b}\left({\mathrm e}^{2k}\right)^n=\dots$+  * The following is kinda odd: 
 +<​code>​ 
 +Integrate[Sin[a*x]*Sin[b*x]/x^2,{x,​0,​Infinity}
 +</​code>​ 
 ----- -----
 === Context === === Context ===
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