Processing math: 100%

Sine function

Function

definiendum sin:CC
definiendum sin(z):=k=0(1)k(2k+1)!z2n+1

θR

sin(θ)=12i(eiθeiθ)

i.e. if ζ:=eiθ, then ζθ¯ζθ=2isin(θ).

Theorem
  • From

bn=ae2kn=bn=a(e2k)n=

we get

bn=asin(2kn)=sin(k(ab1))sin(k(a+b))sin(k)

  • The following is kinda odd:
Integrate[Sin[a*x]*Sin[b*x]/x^2,{x,0,Infinity}]
Integrate[Sin[k*x]*Sin[(k+q)*x]/x^2,{x,0,Infinity}]

Context

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