Processing math: 62%

Growing sequence

Set

context X
definiendum AGrowingSequence(X)
postulate AInfSequence(X)
nN
postulate AnAn+1

Discussion

Ramifications

For falling sequences we have: lim.

For growing sequences we have: \lim_{n\to\infty}A_n=\bigcup_{n=1}^\infty A_n.

Predicates

predicate A_n\uparrow \hat A \equiv A\in \mathrm{GrowingSequence}(X)\ \land\ \lim_{n\to\infty}A_n=\hat A

Parents

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